posted by Rebecca .
You can purchase hydrochloric acid in a concentrated form that is 37.0 hcl by mass and has a density of 1.20g/mL. Describe how exactly you would prepare 2.85 L of 0.500 M HCL from the concentrated solution.
Calculate the molarity of the concentrated HCl. You made a typo and omitted the % after 37.
M HCl = 1000mL x 1.20g/mL x 0.37 x (1 mol/36.5g) = about 12.2M
Then mL1 x M1 = mL2 x M2
mL1 x 12.2M = 2850 mL x 0.500
Solve for mL 1 you need.
Take mL you've calculated, add to a 500 mL volumetric flask, add distilled water to the mark on the flask, mix thoroughly.