posted by Elle .
A 74.2-kg climber is scaling the vertical wall of a mountain. His safety rope is made of a material that, when stretched, behaves like a spring with a spring constant of 1.62 x 103 N/m. He accidentally slips and falls freely for 0.959 m before the rope runs out of slack. How much is the rope stretched when it breaks his fall and momentarily brings him to rest?
The potential energy going into the rope is .959+x meters (x is the distance the rope stretches).
the stored energy in the rope is 1/2 k x^2
set them equal, solve for x.