posted by At Least I Am Persistent. .
A current of 5.41 A is pass through a Ni(NO3)2 solution. How long (in hours) would this current have to be applied to plate out 7.30 g of nickel?
Your "persistence" is called spamming.
You're banned from posting for a few days.
You may not be able to post for a few days but I think you can read responses. Here is how you do this problem.
You want 7.30g Ni.
96,485 coulombs will deposit 58.7g/2 or 29.35g Ni. so you will need
96,485 coulombs x (7.35/29.35) = approx 24,000 coulombs but that's an estimate and you should redo this calculation as well as all that follow.
Coulombs = amperes x seconds.
You know coulombs and amperes, solve for seconds and convert to hours.