tickets for a school play cost $4 for adults and $2 for students at the end of the play the school sold a total of 105 tickets and collected $360 how much of each type of tickets did they sell
4A+2S=360
A+S=105
does that help?
To solve this problem, we can use a system of equations. Let's assume that the number of adult tickets sold is represented by 'a' and the number of student tickets sold is represented by 's'.
From the given information, we can form two equations:
1) The total number of tickets sold: a + s = 105
2) The total amount collected from ticket sales: 4a + 2s = 360
To solve this system of equations, we can use substitution or elimination method. Let's use the substitution method:
We can rewrite equation 1 as "a = 105 - s" and substitute it into equation 2:
4(105 - s) + 2s = 360
420 - 4s + 2s = 360
-2s + 420 = 360
-2s = 360 - 420
-2s = -60
s = -60 / (-2)
s = 30
Now that we have the number of student tickets sold (s = 30), we can substitute it back into equation 1 to find the number of adult tickets sold:
a + 30 = 105
a = 105 - 30
a = 75
Therefore, the school sold 75 adult tickets and 30 student tickets.