The Ksp of tin(II) hydroxide, Sn(OH)2, is 5.45 × 10-27. Calculate the solubility of this compound in g/L.
1.695*10^-7
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............Sn(OH)2 ==> Sn^2+ + 2OH^-
I............solid.......0........0
C............solid.......x........2x
E............solid.......x........2x
Ksp = (Sn^2+)(OH^-)^2
5.45E-27 = (x)(2x)^2
Solve for x = solubility in mols/L.
Then grams = mols x molar mass