The Ksp of tin(II) hydroxide, Sn(OH)2, is 5.45 × 10-27. Calculate the solubility of this compound in g/L.
1.695*10^-7
Heather is correct. Atta girl Heather. You da real mvp
Heather is correct
how is heather incorrect?
heather is right
heather is correct ya'll
............Sn(OH)2 ==> Sn^2+ + 2OH^-
I............solid.......0........0
C............solid.......x........2x
E............solid.......x........2x
Ksp = (Sn^2+)(OH^-)^2
5.45E-27 = (x)(2x)^2
Solve for x = solubility in mols/L.
Then grams = mols x molar mass
The answer is 1.10861×10^-9 in sapling. Heather truly does suck.
she right, you'll crazy just say thanks for the answer
thank you
Poor Heather she was only trying. LOL!
Heather is correct, even on sapling. thank you heather, nicely done on the math. the rest of you who say she isn't need to check yourselves
heather played u, its 1.108*10^-9
how can u be so sure, it all depends on what their definition of RIGHT is....
I don't know what's going on here, I just need some answers xD
Heather is so wrong it's not even funny I don't know how she even got her number just use a calculator.
yall buggin heather's right the problem says the answer is in g/L...jus convert foo
Heather sucks.
the correct answer is 1.10861*10^-9 on sapling.
Heather sucks.