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what mass of sulphuric acid must be added to a 750 ml to have a ph of 2.27
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concentrated aqueous sulphuric acid is 98% sulphuric acid by mass and has a density of 1.80 g/l. Volume of acid required to make
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98% by weight means 98 gm H2SO4 in 100 gm solution or 98 g H2SO4 in 2 g water. Number of moles of
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magnesium reacts with sulphuric acid according to the equation:
Mg3 + H2SO4=MgSO4 + H2 a 250cubic centimetre aqueous solution
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Where does the 3 from Mg3 come from. The equation is Mg + H2SO4 ==> MgSO4 + H2 a. mols Mg =
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If 15g of Sodium Hydroxide are treated with sulphuric acid to produce sodium sulphate, how many grams of sulphuric acid are
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2NaOH + H2SO4 ==> 2H2O + Na2SO4 Here is a worked example. Just follow the steps.
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Suppose you need 2.0 L of 6.0 M sulphuric acid, and you have a bottle of concentrated acid of 18.0 M sulphuric acid. a). How
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To determine how much of the concentrated 18.0 M sulphuric acid is needed to prepare a 2.0 L, 6.0 M
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Thanks a lot:)
So just to confirm: normally for any chemical bought from manufacturer, if it is not stated, the % usually means
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I think your conclusion is wrong. You are correct that the percent on a bottle of H2SO4 means w/w.
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question 7 and 8.
7. To prepare 500~cm^{3} of 0.15 mol/dm³ sulphuric acid from a stock solution of 2.0~mol/dm^{3} sulphuric
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To solve question 7, we can use the molarity equation: M1V1 = M2V2 M1 is the molarity of the stock
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Question 7 to 8
7. To prepare 500~cm^{3} of 0.15 mol/dm³ sulphuric acid from a stock solution of 2.0~mol/dm^{3} sulphuric acid.
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7. To prepare 500 cm^3 of 0.15 mol/dm³ sulphuric acid: We can use the formula: C1V1 = C2V2 C1 =
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20.0cm3of a solution containing 4g/L of sodium hydroxide was neutralize by 8cm of dilute sulphuric acid
Calculate the
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First, let's calculate the amount (in moles) of sodium hydroxide present in the 20.0 cm^3 solution.
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With relation to Avogadro's Constant:
How many hydrogen ions are present in 3 moles of dilute sulphuric acid? As sulphuric acid
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1 mol contains 6.02E23 H2SO4 molecules. 3 mol contains 3*6.02E23 H2SO4 molecules. There are 2 atoms
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Molality of sulphuric acid is 8.01m and its density is 1.354g/ml. Find molarity and mole fraction of sulphuric acid?
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Your solution is not correct. If the solution has a density of 1.354 g/mL then the mass of the
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