math
posted by Anonymous .
if four out every seven individuals in a population of armadillos carry a gene for a defective enzyme, how many individuals carry the normal gene in a population of 869 armadillos?

(3/7) * 869 = 2607/7 = 372.4
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if four out of every seven individuals in a population of armadillos carry a gene for a defective enzyme, how many individuals carry the normal gene in a population of 869 armadillos?