Calculus

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I need help finding the derivative of
√3x/(x^2-4) at x=3

  • Calculus -

    y = √(3x)/(x^2-4)

    y' =

    -√3(3x^2+4)
    ------------------
    2√x (x^2-4)^2

    At x=3 that is

    -√3(31)/(2√3 (25)) = -31/50

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