Calculus
posted by Annie .
I need help finding the derivative of
√3x/(x^24) at x=3

Calculus 
Steve
y = √(3x)/(x^24)
y' =
√3(3x^2+4)

2√x (x^24)^2
At x=3 that is
√3(31)/(2√3 (25)) = 31/50
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