square route of 2 plus the square route of 1 plus k = 2.24
The questions is like this: sqr(2) + sqr(1), and the asnwer is 1 + sqr(2), or in decimal form: 2.4142
1.4142 + 1 + k = 2.24
2.4142 + k = 2.24
k = -0.1742
unless it's
√2 + √(1+k) = 2.24
√(1+k) = .8258
1+k = .6819
k = -.3181
check:
√2 + √.6819 = 2.24
ah - I see this is a rehash of
√2 + √(1+k) = √5
√(1+k) = √5-√2
1+k = 5-2√10+2
k = 6-2√10
To find the value of k in the equation √2 + √1 + k = 2.24, we need to isolate the variable k on one side of the equation.
Step 1: Start by subtracting the square roots from both sides of the equation:
√2 + √1 + k - (√2 + √1) = 2.24 - (√2 + √1)
Step 2: Simplify the left side of the equation:
√2 + √1 + k - √2 - √1 = 2.24 - √2 - √1
Step 3: Combine like terms:
(√2 - √2) + (√1 - √1) + k = 2.24 - √2 - √1
Step 4: Simplify the equation further:
0 + 0 + k = 2.24 - √2 - √1
Step 5: Combine the numbers on the right side of the equation:
k = 2.24 - √2 - √1
Now, using a calculator, we can approximate the value of k:
k ≈ 2.24 - 1.414 - 1
k ≈ 2.24 - 1.414 - 1
k ≈ 0.826
Therefore, the approximate value of k is 0.826.