the lcm of two numbers is 60. one of the numbers is 20. the other number is even and has only two prime factors. what's the other number
How about 6 ?
I don't know just give me the answer people
It is '15' because if you find the factors of 60, only 15 is the number which can't divide 20 but 60 can be divided by it :) ;)
To find the other number, we can use the concept of the least common multiple (LCM) between two numbers. The LCM is the smallest multiple common to both numbers.
Given that the LCM of two numbers is 60, one of the numbers is 20, and the other number has only two prime factors, we can find the second number by following these steps:
Step 1: Write the prime factorization of the first number.
The prime factorization of 20 is 2 * 2 * 5.
Step 2: Determine the factors of the LCM that are not already present in the prime factorization of the first number.
The prime factorization of 60 is 2 * 2 * 3 * 5.
Comparing the prime factorizations of 20 and 60, we see that the only prime factor not present in the first number's factorization is 3.
Step 3: Calculate the second number.
Since the other number has only two prime factors, and one of them is 3, the second number can be written as 3 * x, where x represents the remaining prime factor(s).
Therefore, the second number is 3 * (2 * 5) = 3 * 10 = 30.
Thus, the other number is 30.