what is the solution of 3x^+27=0
you left out the exponent
3x^ ????
3x^2
To find the solution to the equation 3x^2 + 27 = 0, we can follow these steps:
Step 1: Subtract 27 from both sides of the equation to isolate the quadratic term, 3x^2.
3x^2 + 27 - 27 = 0 - 27
3x^2 = -27
Step 2: Divide both sides of the equation by 3 to solve for x^2.
(3x^2) / 3 = (-27) / 3
x^2 = -9
Step 3: Take the square root of both sides to find the possible values of x.
√(x^2) = ±√(-9)
x = ±√(-9)
Understanding that the square root of a negative number is considered an imaginary number, we can rewrite the square root of -9 as the square root of 9 * the square root of -1. The square root of 9 is 3, and the square root of -1 is represented by the imaginary unit "i."
So, the solutions to the equation 3x^2 + 27 = 0 are x = -3i and x = 3i.