posted by lynda .
The weight of a can made from a machine is normally distributed with a mean of 25 grams and a
standard deviation of 0.4 grams. What percentage of the cans from this machine would not meet the
minimum required weight of 24 grams? Round to the nearest hundredth of a percent
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Multiply by 100 to get the percentage.