Physics
posted by Maryam .
At t=0, a particle leaves the origin with a velocity 6m/s in the positive x direction and moves in the xy plane with a constant acceleration (2i4j)m/s2
How far the particle from the origin at t=1 ?

displacement=vi*t+1/2 a t^2
= 6i*1+1/2 (2i4j)*1
combine terms. Then how far is = sqrt (icomponent^2+jcomponent^2)
The only issue, is x direction the i direction?
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