# PHYSICS(HELP)

posted by .

A satellite with a mass of ms = 7.00 × 103 kg is in a planet's equatorial plane in a circular "synchronous" orbit. This means that an observer at the equator will see the satellite being stationary overhead (see figure below). The planet has mass mp = 8.59 × 1025 kg and a day of length T = 1.1 earth days (1 earth day = 24 hours).

(a) How far from the center (in m) of the planet is the satellite?

(b) What is the escape velocity (in km/sec) of any object that is at the same distance from the center of the planet that you calculated in (a)?

• PHYSICS(HELP) -

set gravitation force equal to centripetal force

GMe*m/(r^2)=mwr where w=2PI/Period

so change T to seconds, solve for r

• PHYSICS(HELP) -

R=(G*mp*T^2/(4*pi^2))^(1/3)
Vesc=sqrt(2*mp*G/R)

• PHYSICS(HELP) -

T=24h?

• PHYSICS(HELP) -

My answer is not showing correct, using these formulas.. What am I doing wrong??

• PHYSICS(HELP) -

Is G=6.67*10^-11???

• PHYSICS(HELP) -

G is the same everywhere. Its the T that we need to input carefully.

• PHYSICS(HELP) -

My T=1.4 Earth days.. Should I convert them to seconds?? which is= 120960 sec???

• PHYSICS(HELP) -

Also which formula should I use??

• PHYSICS(HELP) -

My T is also 1.4. Someone asked me to divide that by 8.6x10^4.

• PHYSICS(HELP) -

yes @anonymous u just convert it into sec onds and solve the equation which mac has given . u'll get the right answer ..just don't forget the r^3 and t^2..yes it will give u very large numbers :( even i was obsessed . keep trying

• PHYSICS(HELP) -

@kunoi yes man..! for the b bit u have to divide the final answer by 86400 bcs 24*60*60 is 86400seconds :)

## Similar Questions

1. ### Physics

A satellite of mass 220 kg is launched from a site on Earth's equator into an orbit at 200 km above the surface of Earth. (a) Assuming a circular orbit, what is the orbital period of this satellite?
2. ### Physics

A satellite of mass 210 kg is launched from a site on Earth's equator into an orbit at 210 km above the surface of Earth. (a) Assuming a circular orbit, what is the orbital period of this satellite?
3. ### physics

A satellite with a mass of ms = 7.00 × 103 kg is in a planet's equatorial plane in a circular "synchronous" orbit. This means that an observer at the equator will see the satellite being stationary overhead (see figure below). The …
4. ### physics

A satellite with mass 6.00*10^3 is in the equatorial plane in a circular orbit. The planet's mass = 6.59 *10^25 and a day of length is 1.6 earth days. How far from the center (in m) of the planet is the satellite?
5. ### physics

A satellite with mass 6.00*10^3 is in the equatorial plane in a circular orbit. The planet's mass = 6.59 *10^25 and a day of length is 1.6 earth days. How far from the center (in m) of the planet is the satellite?
6. ### Physics 141

A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.60 104 m/s, and the radius of the orbit is 5.50 106 m. A second satellite also has a circular orbit around this same planet. The orbit of this …
7. ### Physics 141

A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.60 104 m/s, and the radius of the orbit is 5.50 106 m. A second satellite also has a circular orbit around this same planet. The orbit of this …
8. ### physics

A satellite of mass 205 kg is launched from a site on Earth's equator into an orbit at 200 km above the surface of Earth. (a) Assuming a circular orbit, what is the orbital period of this satellite?
9. ### Physics

A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 2.15 × 104 m/s (Va) and the radius of the orbit is 5.15 × 106 m (ra). A second satellite also has a circular orbit around this same planet. …
10. ### Physics

A satellite is orbiting a distant planet of mass 9.6e25 kg and radius 86700 km. The satellite orbits at a height of 8610 km above the surface of the planet. a) Determine the acceleration due to gravity at the location of the satellite …

More Similar Questions