posted by Anonymous .
1. find the equation of the tangent line at x=1 to y=f(x) where f(x)=(3x^2)/(5x^2+7x)
Can someone help walk me through the steps of this problem. Do I start with finding the derivative of the function using the quotient rule?
sorry I didn't mean to repost this. When I refreshed by computer did it automatically for whatever reason. I posted the same question below but if someone can help and wants to answer here that's fine too.
Unless there's a typo,
y = (3x)/(5x+7), so
y(1) = 1/4
y' = 21/(5x+7)^2
y'(1) = 112/363
Now you have a point and a slope, so the equation of the line is dead simple.