A bottle of 12.0 M hydrochloric acid has only 35.7 mL left in
it. What will the HCl concentration be if the solution is
diluted to 250.0 mL?
12.0M x (35.7/250.0) = ?
or you can use
c1v1 = c2v2
c = concn
v = volume
12.0*35.7 = c2*250
c2 about 1.7M
Well, let me do some calculations while juggling some numbers and balancing equations. *starts juggling imaginary bottles*
If you dilute 35.7 mL of 12.0 M hydrochloric acid to a final volume of 250.0 mL, we need to find out what the new concentration will be.
To do that, we can use the equation:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Plugging in the numbers, we get:
(12.0 M)(35.7 mL) = (C2)(250.0 mL)
Now, solving for C2, we get:
C2 = (12.0 M)(35.7 mL) / (250.0 mL)
*Circus music intensifies* And after doing some jaw-dropping math tricks, the concentration of the diluted solution will be...
*takes a deep breath*
1.7144 M!
So, the HCl concentration will be approximately 1.7144 M when the solution is diluted to 250.0 mL. Ta-da! *sprinkles confetti*
To find the HCl concentration after the solution is diluted to 250.0 mL, you can use the equation:
C1V1 = C2V2
Where:
C1 = initial concentration of HCl (12.0 M)
V1 = initial volume of HCl (35.7 mL)
C2 = final concentration of HCl (unknown)
V2 = final volume of HCl (250.0 mL)
Plugging the given values into the equation, we can solve for C2:
(12.0 M)(35.7 mL) = C2(250.0 mL)
To solve for C2, divide both sides of the equation by 250.0 mL:
(12.0 M)(35.7 mL) / 250.0 mL = C2
Calculating the expression on the left side of the equation:
(12.0 M)(35.7 mL) / 250.0 mL = 1.71 M
Therefore, the HCl concentration will be 1.71 M if the solution is diluted to 250.0 mL.
To find the final concentration of the hydrochloric acid solution after dilution, we can use the equation:
M1V1 = M2V2
Where:
M1 = initial concentration of the solution
V1 = initial volume of the solution
M2 = final concentration of the solution
V2 = final volume of the solution
Given:
M1 (initial concentration) = 12.0 M
V1 (initial volume) = 35.7 mL
V2 (final volume) = 250.0 mL
We can rearrange the equation to solve for M2:
M2 = (M1 * V1) / V2
Now, we can substitute the values into the equation and calculate the final concentration:
M2 = (12.0 M * 35.7 mL) / 250.0 mL
First, let's convert the volumes to liters to make the units consistent:
V1 (initial volume) = 35.7 mL * (1 L / 1000 mL) = 0.0357 L
V2 (final volume) = 250.0 mL * (1 L / 1000 mL) = 0.2500 L
Now we can substitute the values:
M2 = (12.0 M * 0.0357 L) / 0.2500 L
Calculating the expression:
M2 = 0.4284 M
Therefore, the HCl concentration will be 0.4284 M after dilution.