Calculus Please Help??

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Evaluate the integral (3x^2-16x-19)/(x^3-4x^2-3x+18)

  • Calculus Please Help?? -

    Have you done the method of partial fractions yet?

  • Calculus Please Help?? -

    Yes, I know how to get variables. I got b=-8, c=1, and a=2, but I don't know how to get an integral as an answer. I need help integrating 2 other problems I will post as well, if you can help me.

  • Calculus Please Help?? -

    1. (-5x^2+10x-12)/(x-5)(x^2+4)
    2. (-8x-28)/((x-2)(x+9))

    I know how to integrate, I just don't know how to get an integral, after finding a,b,c, and from that point

  • Calculus Please Help?? -

    So you were able to use partial fractions to decompose it to

    -8/(x-3)^2 + 2/(x-3) + 1/(x+2)
    that was the hardest part, the rest is easy

    isn't the integral of -8/(x-3)^2 equal to 8/(x-3) ?

    as to the others, you should recognize the pattern of the derivative of a log function

    recall that is y = ln (u)
    then dy/dx = (du/dx) / ln (u)

    so if we integrate
    -8/(x-3)^2 + 1/(x+2) + 2/(x-3)

    we get

    8/(x-3) + ln(x+2) + 2ln(x-3) + constant

  • Calculus Please Help?? -

    For your 2nd part,
    did you get the partial fraction breakdown of

    -2x/(x^2+4) - 3/(x-5) from (-5x^2 + 10x - 12)/((x-5)(x^2+4)) ?

    then your integral would be

    -ln(x^2+4) - 3ln(x-5) + a constant

    let me know what you get for your last question.

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