posted by Jay .
Just as a car tops a 47 meter high hill with a speed of 36 km/h it runs out of gas and coasts from there, without friction or drag. How high, to the nearest meter, will the car coast up the next hill?
Vo = 36km/h = 36000m/3600s = 10 m/s.
V^2 = Vo^2 + 2g*h
h = (V^2-Vo^2)/2g
h = (0-10^2)/-19.6 = 5.0 m.