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Just as a car tops a 47 meter high hill with a speed of 36 km/h it runs out of gas and coasts from there, without friction or drag. How high, to the nearest meter, will the car coast up the next hill?

  • Physics -

    Vo = 36km/h = 36000m/3600s = 10 m/s.

    V^2 = Vo^2 + 2g*h
    h = (V^2-Vo^2)/2g
    h = (0-10^2)/-19.6 = 5.0 m.

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