Post a New Question


posted by .

f(x)= 1/x^2-8x-9
g(x)= 1/x^2+3x+2

  • math -

    What is required to find? :3

  • math -


  • math -

    Domain of what?
    If the required is their individual domains:
    1. For f(x) = 1/(x^2 - 8x - 9)
    Note that domain is the set of all possible values of x. In the function, note that the denominator must not be equal to zero because 1/0 is infinity. Therefore, we find the values of x, which the denominator will be zero and restrict the domain to those values:
    f(x) = 1/(x^2 - 8x - 9)
    f(x) = 1/(x-9)(x+1)
    Thus, x is all real numbers except -1 and 9.

    2. For g(x) = 1/(x^2 + 3x + 2)
    The procedure is pretty much the same. We find the values of x which will make the denominator zero:
    g(x) = 1/(x^2 + 3x + 2)
    g(x) = 1/(x+1)(x+2)
    Thus, x is all real number except -1 and -2.

    Hope this helps~ :3

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question