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posted by ROBIN Monday, July 15, 2013 at 9:01pm.

solve for theda given 0<theda<2pi cos theta= - (sqrt 3)/ 2

you know that cos π/6 = √3/2 You also know that cos(x) < 0 in QII,QIII So, ...

so ould it be sin pi.6 and tan pi/6??

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