Two 1.5 kg balls move away from each
other, one traveling 6 m/s to the right, the
other 2 m/s to the left.
What is the magnitude of the total momentum of the system?
Answer in units of kg · m/s
total momentum:
1.5(6R+2L)=1.5(6R-2R)=6Right
magnitude: 6 kg m/s
Well, if one ball is moving to the right and the other to the left, it's like they're on a comedic collision course. They're like two clumsy clowns! And when clumsy clowns collide, the momentum gets a little messy.
To find the magnitude of the total momentum of the system, we need to first calculate the momentum of each ball individually.
The momentum of an object is given by the formula:
Momentum = Mass x Velocity
Let's start with the ball moving to the right. It has a mass of 1.5 kg and a velocity of 6 m/s. So, its momentum is:
Momentum (right ball) = 1.5 kg x 6 m/s
Next, let's look at the ball moving to the left. It also has a mass of 1.5 kg, but its velocity is in the opposite direction (-2 m/s). So, its momentum is:
Momentum (left ball) = 1.5 kg x (-2 m/s)
Now, to find the total momentum of the system, we just need to add these individual momenta together.
Total Momentum = Momentum (right ball) + Momentum (left ball)
Go ahead and calculate the math, and you'll have your answer in units of kg · m/s. Just remember, when clumsy clowns collide, it's bound to be a funny and unpredictable result!
To find the magnitude of the total momentum of the system, we first need to calculate the momentum of each ball separately.
The momentum of an object is given by the formula:
Momentum = mass x velocity
For the first ball moving to the right:
Mass = 1.5 kg
Velocity = 6 m/s
Momentum of first ball = 1.5 kg x 6 m/s = 9 kg·m/s (to the right)
For the second ball moving to the left:
Mass = 1.5 kg
Velocity = -2 m/s (negative because it is moving to the opposite direction)
Momentum of second ball = 1.5 kg x -2 m/s = -3 kg·m/s (to the left)
To find the total momentum of the system, we need to add the individual momenta:
Total momentum = momentum of first ball + momentum of second ball
Total momentum = 9 kg·m/s + (-3 kg·m/s) = 6 kg·m/s
Therefore, the magnitude of the total momentum of the system is 6 kg·m/s.
To find the magnitude of the total momentum of the system, we need to calculate the individual momenta of the two balls and then add them together.
The momentum of an object can be calculated by multiplying its mass (m) by its velocity (v). In this case, both balls have a mass of 1.5 kg.
For the ball moving to the right:
Mass (m1) = 1.5 kg
Velocity (v1) = 6 m/s
For the ball moving to the left:
Mass (m2) = 1.5 kg
Velocity (v2) = -2 m/s (negative sign indicates the opposite direction)
Now let's calculate the momenta:
Momentum of ball 1 (p1) = mass of ball 1 x velocity of ball 1 = m1 * v1
Momentum of ball 1 (p1) = 1.5 kg * 6 m/s = 9 kg·m/s
Momentum of ball 2 (p2) = mass of ball 2 x velocity of ball 2 = m2 * v2
Momentum of ball 2 (p2) = 1.5 kg * -2 m/s = -3 kg·m/s (negative sign indicates the opposite direction)
Now, let's add the momenta of both balls to find the total momentum of the system:
Total momentum (p) = p1 + p2
Total momentum (p) = 9 kg·m/s + (-3 kg·m/s)
Adding 9 kg·m/s to -3 kg·m/s gives us:
Total momentum (p) = 6 kg·m/s
Therefore, the magnitude of the total momentum of the system is 6 kg·m/s.