College Algebra
posted by Jack .
Find all solutions of the equation. Check your solutions in the original equation. (Enter your answers from smallest to largest. Enter NONE in any unused answer blanks.)
16t^2/3 + 40t^1/3 + 25 = 0

let u = t^1/3 so we have
16u^2 + 40u + 25 = 0
(4u+5)^2 = 0
so, 4u+5 = 0
u = 5/4
so the only solution is t = ∛(5/4)