i am 11 less than the product of 7 and 5. i am 5 more than the product of 11 and 2
I'm not so sure if the problem requires the domain (all possible values of the number). Or if the problem requires only one value of the unknown.
Let x be the number.
From the first statement,
x < 7 * 5 - 11
x < 35 - 11
x < 24
From the second statement,
x > 11 * 2 + 5
x > 22 + 5
x > 27
Thus, if the the domain of x is the one required:
(-infinity, 24) U (27, +infinity)
However, if the problem wants a single value of x, the value does not exist because there is no value that is less than 24 which is, at the same, time must be greater than 27, or
(-infinity, 24) ∩ (27, +infinity) = d.n.e.
Hope this helps~ :)
IGNORE THE ABOVE POST LOL. I shouldn't have used greater than and less than signs! @_@
From the first statement,
x = 7 * 5 - 11
x = 35 - 11
x = 24
From the second statement,
x = 11 * 2 + 5
x = 22 + 5
x = 27
Sorry about that. I don't know what I'm thinking lol. ^^;
Hope this helps~ :)
To find the number described in the problem, you will need to perform the operations mentioned.
1. Starting with the first sentence in the problem: "I am 11 less than the product of 7 and 5."
To find the product of 7 and 5, you need to multiply them together: 7 * 5 = 35.
Then subtract 11 from the result obtained above: 35 - 11 = 24.
Therefore, the first number is 24.
2. Moving on to the second sentence: "I am 5 more than the product of 11 and 2."
To find the product of 11 and 2, you multiply them together: 11 * 2 = 22.
Then add 5 to the product obtained above: 22 + 5 = 27.
So, the second number is 27.
In summary:
The first number is 24 and the second number is 27.