Calculus
posted by Tyler .
Find the linear approximation L(x) of
ln(x)at the point a = 12.

L(x)=ln(z)+delta(xz)*dL/dx
L(x)=ln(12)+1/12*(x12)
so for example, what is Ln(13):
Ans: Ln(13)=ln(12)+1/12*1
checking that from a calculator:
ln(12)== 2.48490665
ln(13)== 2.56494936
difference 0.08004271
1/12== 0.0833333333
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