posted by DEEDEE .
According to the equation H2SO4+2NH3 @(NH4)2SO4. What mass of ammonium sulfate will result from the reaction of 5.00 g of NH3?
ok..so write the balance equation;
H2SO4 + 2NH3 --> (NH4)2SO4
this shows that 1 mole of sulphuric acid react with 2 moles of NH3 to produce 1mole of ammonium sulphate. The question asks the mass of (NH4)2SO4 produced by 5.00g of NH3 is used. So focus only on these two; ignore sulphuric acid.
so, mole ratio
2:1 (2mole NH3 produces 1mole (NH4)2SO4).
here's what to do;
1. calculate the mole of NH3 using n = m/Mr where m is the mass in grams and Mr is the molar mass.
2. Use the mole of NH3 to determine the mole of ammonium sulphate using the mole ratio of the two.
3. Use the mole for ammonium sulphate to calculate the mass by using m = nMr where n is the mole you calculated in step 2 and Mr is the molar mass of ammonium sulphate.
Hope that helps.