integral calculus

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integral of sin(x^2) dx

i actually got the ans, but aftr differentiating the answer i am not getting back the question

  • integral calculus -

    let u=x^2
    du= 2x dx

    dx=du/2x
    dx=du/2sqrt(u)

    -1/4 cos u is the integral

  • integral calculus -

    http://www.numberempire.com/integralcalculator.php

    This involves the error function, not an elementary problem. Hannah has made an error.

  • integral calculus -

    I'm sorry about that. Can you explain why there is an error Mr. Pursley? I genuinely don't understand how there is an error.

  • integral calculus -

    Your substitutions are good, but you dropped something. You should have watched the details:

    ∫sin(x^2) dx = ∫sin(u) / 2√u du

  • integral calculus -

    then how do we proceed ??
    is their any solution to this problem?

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