integral calculus

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integral of sin(x^2) dx

i actually got the ans, but aftr differentiating the answer i am not getting back the question

• integral calculus -

let u=x^2
du= 2x dx

dx=du/2x
dx=du/2sqrt(u)

-1/4 cos u is the integral

• integral calculus -

http://www.numberempire.com/integralcalculator.php

This involves the error function, not an elementary problem. Hannah has made an error.

• integral calculus -

I'm sorry about that. Can you explain why there is an error Mr. Pursley? I genuinely don't understand how there is an error.

• integral calculus -

Your substitutions are good, but you dropped something. You should have watched the details:

∫sin(x^2) dx = ∫sin(u) / 2√u du

• integral calculus -

then how do we proceed ??
is their any solution to this problem?

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