# MATH

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the area of a certain rectangle is 288yd squared. the perimeter is 68yd. if you double the length and width,what will be the area and perimeter of the new rectangle?

• MATH -

L*W = 288
2L*2W = 4*L*W = 4*288 = 1152 yds^2.

2L+2W = 68
2(2L+2W) = 2*68 = 136 yds.

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