9x^2-6x-7=0
is it a :
One rational solution
Two rational solutions
Two irrational solutions
One complex solution
Two complex solutions
b^2 - 4ac = 36 - 4(9)(-7) = positive, non-square
so we rate two irrational solutions
check with the many "Related Questions" to yours below.
BTW, the choice of ONE complex solution is never possible
What is the number of real solution of -x^2+9x+7=0
To determine the type of solutions for the equation, we can use the discriminant. The discriminant is calculated using the formula: b^2 - 4ac, where a, b, and c are the coefficients of the quadratic equation in the standard form ax^2 + bx + c = 0.
In this case, a = 9, b = -6, and c = -7. Plugging these values into the discriminant formula, we get: (-6)^2 - 4(9)(-7).
Calculating further: 36 + 252 = 288.
The value of the discriminant is 288. Now, we can analyze the discriminant to determine the type of solutions:
- If the discriminant is positive, then we have two distinct real solutions.
- If the discriminant is zero, then we have one real solution (a repeated root).
- If the discriminant is negative, then we have two complex (or imaginary) solutions.
Since the discriminant is positive (288), we conclude that this quadratic equation has two distinct real solutions.