math

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jim has grades of 84, 65, 76 on three tests. what grade must he obtain on the next test to have an average of exactly 80% for all four tests?

  • math -

    84 + 65 + 76 = 225

    0.8 * 400 = 320

    320 - 225 = 95

  • math -

    ( 84 + 65 + 76 + x ) / 4 = 80

    84 + 65 + 76 + x = 4 * 80

    225 + x = 320

    x = 320 - 225 = 95

  • math -

    (65 + 84 + 76 + x ) / 4 = 80

    (Balance the Equation)

    225 + x = 320 [65 + 84 + 76 + x = 320]

    (Balance the Equation)

    x = 320 - 225 = 95

  • algebra -

    y=5x-3 y=-3x+13

  • math -

    The sum of two consecutive numbers is 37. What are they

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