college algebar

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logb x= logb(x+2)-logb8

  • college algebar -

    What is the question?

  • college algebar -

    logb x= logb(x+2)-logb8
    logx = log [ (x+2)/8 ] , where all logs are base 8
    anti-log it

    x = (x+2)/8
    8x = x+2
    7x = 2

    x = 2/7

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