MATH
posted by CASEY .
Logv3(12) = logv3 (3t^2)  logv3 (3t)
(the v means "log 3" 3 is the base)

remember to divide the terms when subtracting in logarithms.

WAIT ITS t^2 NOT 3t^2

ok, divide throughout by logv3 and then you will get a quadratic equation and solve for t.

But then when i try to factor i get 0=t^23t12

Complete the square method.