posted by CASEY .
Logv3(12) = logv3 (3t^2) - logv3 (3t)
(the v means "log 3"- 3 is the base)
remember to divide the terms when subtracting in logarithms.
WAIT ITS t^2 NOT 3t^2
ok, divide throughout by logv3 and then you will get a quadratic equation and solve for t.
But then when i try to factor i get 0=t^2-3t-12
Complete the square method.