precalculus
posted by Anonymous .
Solve 8sin(pi/4x) = 6 for the four smallest positive solutions
Give your answers accurate to at least two decimal places, as a list separated by commas.

8sin(pi/4x) = 6
sin ((π/4)x) = .75
πx/4 = .84806 or πx/4 = 2.2935
x = 1.07979 or 2.9202
the period of the original sine curve is 2π/(π/4) = 8
so by adding 8 to the above we get the other two x values
x = 1.07979 , 2.2935 , 9.079 , 10.9202