MATHs
posted by Oian .
The three terms x+12, 3x+5 and 2x+25 are the first three terms of an arithmetic progression. What is the value of x?

Solve X by finding common difference....in this case;step 1:3X+5(X+12)=2X+25(3X+5)
step2:3X+5X12=2X+253X5
step3:solve like terms n u'll remain with 3X=27 n then make X subject of the formular by dividing each term by 3...n u'll remain with X= 9