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An airplane pilot wishes to maintain a true course in the direction 250° with a ground speed of 400 mi/hr when the wind is blowing directly north at 60 mi/hr. Approximate the required airspeed and compass heading

  • trig -

    I have a triangle with sides 60 and 400 and the contained angle is 70°
    let the resultant be R
    R^2= 60^2 + 400^2 - 2(60)(400) cos70°
    = 147183.0331
    R = 383.64 mi/h

    finding the angle opposite the 70°
    sinØ/60 = sin70/R
    sinØ = .14696..
    Ø = 8.45°

    so the compass heading is 250 + 8.45 = 258.5°

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