maths

posted by stranger

Find the number of different ordered quadruples (a,b,c,d) of complex numbers such that
a^2=1
b^3=1
c^4=1
d^6=1
a+b+c+d=0

  1. Steve

    visit wolframalpha.com and enter

    solve a^2=1, b^3=1, c^4=1, d^6=1, a+b+c+d=0

    and you can check your details.

  2. Kim

    There are 3 solutions with real numbers and 4 solutions with complex numbers

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