Let f:{0,1}->{0,1} with f(101)=1 and f(x)=0 for x ≠ 101 . In this question, we will run through two iterations of the algorithm.

(a) What is the superposition after the initialization step? Note that you can describe the superposition Σαx|x> by specifying two numbers α101 and αx for x ≠ 101 .

- α101=
- αx for x ≠ 101 =

(b) After the phase inversion in iteration 1?

- α101=
- αx for x ≠ 101 =

(c) After the inversion about mean in iteration 1?

- α101=
- αx for x ≠ 101 =

(d) After the phase inversion in iteration 2?

- α101=
- αx for x ≠ 101 =

(e) After the inversion about mean in iteration 2?

- α101=
- αx for x ≠ 101 =

plz post other answers

Anyone please?

a) 1/sqrt(8), 1/sqrt(8)

b) -1/sqrt(8), 1/sqrt(8)
c) 5/(2*sqrt(8)), 1/(2*sqrt(8))
d) -5/(2*sqrt(8)), 1/(2*sqrt(8))
e) 22/(8*sqrt(8)), -1/(4*sqrt(8))

Thanks Anonymous!

q5 pls

PLease problem 5?

problem 13 pls?

12B pls???

Click on FLu and you see the answers guys.

Finally, anyone for Problem 5 please?

12)b)

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