Let f:{0,1}->{0,1} with f(101)=1 and f(x)=0 for x ≠ 101 . In this question, we will run through two iterations of the algorithm.
(a) What is the superposition after the initialization step? Note that you can describe the superposition Σαx|x> by specifying two numbers α101 and αx for x ≠ 101 .
- α101=
- αx for x ≠ 101 =
(b) After the phase inversion in iteration 1?
- α101=
- αx for x ≠ 101 =
(c) After the inversion about mean in iteration 1?
- α101=
- αx for x ≠ 101 =
(d) After the phase inversion in iteration 2?
- α101=
- αx for x ≠ 101 =
(e) After the inversion about mean in iteration 2?
- α101=
- αx for x ≠ 101 =
plz post other answers
Anyone please?
a) 1/sqrt(8), 1/sqrt(8)
b) -1/sqrt(8), 1/sqrt(8)
c) 5/(2*sqrt(8)), 1/(2*sqrt(8))
d) -5/(2*sqrt(8)), 1/(2*sqrt(8))
e) 22/(8*sqrt(8)), -1/(4*sqrt(8))
Thanks Anonymous!
q5 pls
PLease problem 5?
problem 13 pls?
12B pls???
Click on FLu and you see the answers guys.
Finally, anyone for Problem 5 please?
12)b)
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