Math
posted by Crystal .
Precalc
(1+i)^3
and
the cube root of 8i

(1+i) = (√2,pi/4)
so, (1+i)^3 = (2√2,3pi/4) = (2+2i)
8i = (8,pi/2)
(8i)^(1/3) = (2,pi/6) = (√3+i)
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