A skier of mass 66 kg skis straight down a 11° slope at constant velocity. Draw a free-body diagram of the skier with the various external forces acting on her. Include the force of air resistance, which is directed opposite the velocity. (Do this on paper. Your instructor may ask you to turn in this work.)
I would include upward forces of wind resistance,surface resistance, vertical support from the slope, and gravity downward (which has a component down the slope and normal)
To draw a free-body diagram of the skier with the various external forces acting on her, we need to consider the following forces:
1. Gravitational force (Weight): This force is always directed vertically downwards and can be represented by a downward arrow pointing towards the center of the Earth. The magnitude of this force can be calculated using the formula: weight = mass * acceleration due to gravity.
2. Normal force: This force is perpendicular to the surface on which the skier is skiing and acts in the opposite direction of the gravitational force. It can be represented by an upward arrow perpendicular to the slope.
3. Friction force: Since the skier is moving at a constant velocity, the friction force acting on her is equal in magnitude and opposite in direction to the gravitational force. It can be represented by an arrow pointing upwards along the slope.
4. Air resistance: The force of air resistance is directed opposite to the skier's velocity. It can be represented by an arrow pointing upwards opposite to the direction of motion.
Please note that the magnitude and direction of each force will depend on the specific values of the mass, slope angle, and other factors given in the question.
To draw a free-body diagram of the skier with the various external forces acting on her, you would need to consider the forces acting on the skier. Here are the steps to draw the free-body diagram:
1. Start with a diagram that represents the skier as a point or a simple stick figure.
2. Draw a downward arrow representing the weight (mg) acting vertically towards the center of the Earth. The magnitude of the weight can be calculated as the mass of the skier (66 kg) multiplied by the acceleration due to gravity (9.8 m/s^2).
3. Draw a horizontal arrow in the direction of the slope to represent the component of the weight parallel to the slope. This can be calculated as the weight multiplied by the sine of the angle of the slope (11°).
4. Draw a vertical arrow perpendicular to the slope to represent the normal force (N). The normal force is the force exerted by the ground on the skier, perpendicular to the surface, and it counteracts the component of the weight perpendicular to the slope. It is equal in magnitude but opposite in direction to the component of the weight perpendicular to the slope.
5. Draw an arrow in the direction opposite to the velocity of the skier to represent the force of air resistance. The magnitude of air resistance depends on various factors such as the velocity of the skier and the cross-sectional area presented by the skier to the wind. In this case, it is given that the skier is moving at a constant velocity, so the magnitude of the air resistance is equal to and opposite the magnitude of the component of the weight parallel to the slope.
The free-body diagram should include these forces: weight, component of weight parallel to the slope, normal force, and the force of air resistance.