math
posted by ES .
Camern is wrapping a present. She does not want any left over wrapping paper. How much wrapping paper does she need to buy. The length of the box is 15in,
the width is 3in and the height in 7 in.
I did it this way.
front and back(height)
SA=lw*2
SA=15(7)2
SA=210in squared
Sides( width)= SA=lw*2
SA=3(7)2= 42 in squared
Top and bottom(length
SA=15(3)2
SA=90in squared
Total surface areais SA=210=42=90=342in squared
He must buy 342 in squared of wrapping paper
Did I do all the steps correctly.
Thanks

As = 2(W*h + L*h + L*W)
As = 2(21 + 105 + 45) = 2(171)=342 in^2=
Surface area.
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