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algebra

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The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 50 amps when the resistances is 20 ohms. What is the current when the resistance is 60 ohms?

  • algebra -

    I = k/R
    50 = k/20, so k = 1000, making

    I = 1000/R
    I(60) = 1000/60 = 16.67

  • algebra -

    if y varies directly as x and y = 9 when x =2 find when x =10

  • algebra -

    E = I*R = 50 * 20 = 1000 Volts = Supply
    voltage.

    I = E/R = 1000/60 = 16.67 Amps.

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