Physics

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When a man in a cage whose weight is 1000N pulls a rope that is attached on a cage around a fixed pulley,the force he exerts on the floor of the cage is 450N ,if the cage weigh 250N ,find the acceleration

  • Physics -

    I don't get the picture...a man in a cage pulls a rope attached to the cage..

  • Physics -

    Picture it like this:the rope is attached on top of the cage then from there it passes around a fixed pulley so the man in the cage is pulling the rope down from the pulley.PLEASE HELP ME Bobpursley

  • Physics -

    The weight of cage + man is 1250 N and their combined mass is
    Mtotal = Wtotal/g = 127.6 kg.

    The man and cage accelerate at the same rate, a. Let F be the rope tension force. Consider all forces on the man, including weight and the upward floor force. The man's mass is 102 kg
    F - Wman + 450 = F - 550 = 102*a
    Now consider all exernal forces on man and cage together:
    F -1250 = 127.6 a
    Combining the two results in
    700 = -25.6 a
    a = -0.0366 m/s^2

  • Physics -

    I think u have to also take

    T-f-Wchair=McA

  • Physics -

    U did a mistake
    Wtotal/g=127.55

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