What is the concentration (in M) of an ammonia (NH3) solution if 12.23 grams of ammonia are dissolved to make a 520 mL solution?
mols NH3 = grams/molar mass
Then M = mols/L solution.
To find the concentration (in M) of an ammonia (NH3) solution, you need to calculate the number of moles of ammonia in the solution, and then divide that by the volume of the solution in liters.
Step 1: Calculate the number of moles of ammonia (NH3) in the solution.
To do this, you'll need to use the molar mass of ammonia (NH3), which is the sum of the atomic masses of the elements in one molecule of ammonia. The atomic masses are as follows:
Nitrogen (N) = 14.01 g/mol
Hydrogen (H) = 1.01 g/mol
Molar mass of ammonia (NH3) = (14.01 g/mol) + (3 * 1.01 g/mol) = 17.04 g/mol
Now, you can calculate the number of moles using the given mass of ammonia:
Number of moles = Mass / Molar mass
Number of moles = 12.23 g / 17.04 g/mol
Step 2: Convert the volume of the solution to liters.
The given volume is in milliliters (mL). To convert it to liters, divide by 1000:
Volume (L) = 520 mL / 1000
Step 3: Calculate the concentration (in M).
Concentration (M) = Number of moles / Volume (L)
Now you have all the information needed to calculate the concentration:
Concentration (M) = (12.23 g / 17.04 g/mol) / (520 mL / 1000)
Simplifying this expression will give you the concentration of the ammonia solution in moles per liter (M).