# calculus

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Calculate the indefinite integral:

∫(4x-3/x)dx

• calculus -

INT 4 dx - 3INTdx/x

4x-3lnx + Constant

Or you could have meant this (check parenthesis )

INT( 4x dx-3dx/x)=2x^3 -3lnx + C

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Alright, I want to see if I understand the language of these two problems and their solutions. It asks: If F(x) = [given integrand], find the derivative F'(x). So is F(x) just our function, and F'(x) our antiderivative?

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