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Math

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f(x)=√(x)(x-4)
find the critical number

  • Math -

    Assuming you meant
    f(x) = √((x)(x-4))
    f'(x) = (x-2)/√((x)(x-4))
    So, x=2 is the critical value
    except that f(x) is not defined for 0<x<4

    If you meant f(x) as written,
    f'(x) = (3x-4)/(2√x)
    and the critical value is x = 4/3

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