Math

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Find the dy/dx for each of the following

1)y=ln(2x^6-15)
2)y= 3√ 2x^2-3x-1/5
3) y= x^4/x^2+1

  • Math -

    1. dy/dx = 12x^5 /(2x^6 - 15) ---- routine

    2. dy/dx = 6√2 x - 3 ---- routine

    3. the way you typed it,
    y = x^4/x^2 + 1
    y = x^2 + 1
    dy/dx = 2x

    if you meant x^4/(x^2+ 1) , then you would use the quotient rule. See how critical it is to use brackets ?

  • Math -

    there is no brackets for question 3. Although i am still confused. would you be able to give step by step solutions?

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