A block of aluminum with a volume of 98.5 cm3 absorbs 67.4 J of heat. If its initial temperature was 32.5 °C, what is its final temperature? (density of aluminum = 2.70 g/cm3)
I do not understand how to get the answer
Use density to find mass; i.e., mass = volume x density.
Then q = mass Al x specific heat Al x (Tfial-Tinitial)
To solve this problem, you need to use the formula:
Q = mcΔT
Where:
Q is the heat absorbed (in Joules)
m is the mass of the aluminum block (in grams)
c is the specific heat capacity of aluminum (in J/g°C)
ΔT is the change in temperature (in °C)
To find the mass of the aluminum block, you need to use its volume and density. The formula for density is:
density = mass / volume
Rearranging the formula, you can find the mass:
mass = density * volume
Now you have the mass and can proceed with the calculation.
1. Calculate the mass of the aluminum block:
mass = density * volume
mass = 2.70 g/cm3 * 98.5 cm3
2. Calculate the heat absorbed:
Q = mcΔT
67.4 J = mass * specific heat capacity * ΔT
3. Rearrange the equation to solve for ΔT:
ΔT = Q / (mass * specific heat capacity)
4. Calculate the change in temperature:
ΔT = 67.4 J / (mass * specific heat capacity)
Once you have ΔT, you can calculate the final temperature by adding the change in temperature to the initial temperature:
final temperature = initial temperature + ΔT
Now you can substitute the known values and calculate the final temperature.