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Out of 4 architects, 6 engineers and 9 electricians, how many ways can a group of 6 people be formed to attend a forum if:
a. there is an equal number of architects, engineers and electricians
b. two particular engineers cannot be in the committee?
c. there are at least 3 electricians?

  • Math -

    a. equal number of each
    Combinations again..

    architects 4!/(2!2!)

    engineers 6!/(2!4!)

    electricians 9!/(2!7!)

    b. remove the 2 engineers from the choices which would leave 4 architechts, 4 engineers and 9 electricians Now, we have 17 to choose from to make a group of 6.

    17!/(6! 11!)

  • Math -

    Thanks much :)

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