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If cos A=3/5 and A is acute,find sin A,tan A,and sec A.

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    Use a2 + b2 = c2 of the right triangle to find the length of the missing side. c=hypotenuse which in this case is 5. 3^2 + b^2 = 5^2
    9 + b^2=25
    b^2=16
    b=4

    sin=opposite over hypotenuse which is 4/5
    tan=opposite over adjacent which is 4/3
    sec=the reciprocal of cosine which is 5/3 (just change the top and bottom numbers of cosine to get secant)

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